Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
He | 858 | 50 | 2 | 25.0000 |
It’s | 236 | 22 | 1 | 22.0000 |
She | 399 | 19 | 1 | 19.0000 |
On | 206 | 18 | 1 | 18.0000 |
The | 4422 | 271 | 16 | 16.9375 |
But | 626 | 33 | 2 | 16.5000 |
In | 806 | 45 | 3 | 15.0000 |
And | 427 | 29 | 2 | 14.5000 |
We | 830 | 56 | 4 | 14.0000 |
It | 840 | 39 | 4 | 9.7500 |
For | 338 | 19 | 2 | 9.5000 |
They | 443 | 28 | 3 | 9.3333 |
As | 312 | 18 | 2 | 9.0000 |
To | 174 | 18 | 2 | 9.0000 |
All | 165 | 9 | 1 | 9.0000 |
That’s | 56 | 8 | 1 | 8.0000 |
While | 156 | 8 | 1 | 8.0000 |
This | 673 | 32 | 4 | 8.0000 |
Last | 86 | 8 | 1 | 8.0000 |
Even | 98 | 7 | 1 | 7.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Nov | 139 | 1 | 22 | 0.0455 |
kind | 146 | 1 | 11 | 0.0909 |
tried | 74 | 1 | 8 | 0.1250 |
League | 57 | 1 | 7 | 0.1429 |
a number | 69 | 1 | 7 | 0.1429 |
Valley | 104 | 1 | 6 | 0.1667 |
exciting | 27 | 1 | 6 | 0.1667 |
number | 250 | 2 | 11 | 0.1818 |
a lot | 253 | 3 | 16 | 0.1875 |
29 | 52 | 1 | 5 | 0.2000 |
provides | 70 | 1 | 5 | 0.2000 |
sometimes | 67 | 1 | 5 | 0.2000 |
instead | 79 | 1 | 5 | 0.2000 |
the public | 86 | 1 | 5 | 0.2000 |
usually | 58 | 1 | 5 | 0.2000 |
Israel | 53 | 1 | 5 | 0.2000 |
nice | 59 | 1 | 5 | 0.2000 |
sort | 48 | 1 | 5 | 0.2000 |
eight | 122 | 1 | 5 | 0.2000 |
forced | 53 | 1 | 5 | 0.2000 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II